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14x^2+45x+25=0
a = 14; b = 45; c = +25;
Δ = b2-4ac
Δ = 452-4·14·25
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-25}{2*14}=\frac{-70}{28} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+25}{2*14}=\frac{-20}{28} =-5/7 $
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